Yer wish is my command. I'll try to have one in p.b.i by this afternoon. I'm
going to be away this weekend at a family reunion... so if I don't make it I'll
get it on Monday

Josh

Mike Weber wrote:

> How about a picture explaining all this???
> "Nieminen Juha" <war### [at] sarakerttunencstutfi> wrote in message
> news:38ad1899@news.povray.org...
> >   Yes, the weighted average of the three vertex normals. The weight is the
> > inverse distance of the point from the vertex (ie. when the point is
> exactly
> > at the vertex, the weight for that normal is 1 and for the other two it's
> 0;
> > when it's exactly in the middle of the triangle the weight for all normals
> > will be 1/3).
> >
> > --
> > main(i,_){for(_?--i,main(i+2,"FhhQHFIJD|FQTITFN]zRFHhhTBFHhhTBFysdB"[i]
> > ):5;i&&_>1;printf("%s",_-70?_&1?"[]":" ":(_=0,"\n")),_/=2);} /*- Warp -*/

--
Josh English
eng### [at] spiritonecom
"May your hopes, dreams, and plans not be destroyed by a few zeros."

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